Calculate the degree of ionisation and ph of 0.05 M solution of a weak base having the ionization constant (Kb) is1.77 ? 10 raised to power -5 .Also calculate the ionisation constant of the conjugate acid of this base Share with your friends Share 51 Vartika Jain answered this Dear Student, Now, we know thatKa×Kb=Kw=10-14Therefore, Ka =KwKb=10-141.77×10-5=0.564×10-9Now, Ka=Cα2or, α=KaC=0.564×10-90.05=10.92×10-9=1.044×10-4Now, B(aq) + H2O(aq) → BH+(aq) + OH-(aq) 0.05M 0 0 0.05-α +α +αTherfore,[OH-]=1.044×10-4pOH=-log[OH-] =-log(1.044×10-4) =-0.0187+4=3.981So, pH= 14-pOH= 14-3.981=10.01 52 View Full Answer