Calculate the dimensions of a rectangle whose diagonal is 75m, knowing that is similar to a rectangle with sides measuring 36m*48m respectively?
Let the sides of the rectangle be x and y
diagonal is 75 m.
similar rectangle has two sides 36m. and 48m.
let its diagonal be D
By pythagoras theorem
D2= 362 + 482
D2= 1296 + 2304
D2= 3600
D = 60 m.
So the triangle in first rectangle is similar to triangle in second rectangle
so x/48 = y/36 = 75/60
x/48 = 75/60 y/36 = 75/60
x = 60 m. y = 45m.