calculate the distance between Na+ and Cl- ions in NaCl crystal if its density is 2.165 gcm-3 (molar mass of NaCl = 58.5gmol-1 NA = 6.02 x 10 23 mol-1)
For NaCl
M = 58.44g, z=4, d=2.165 g/cm3
Substituting the values in ..
d = (Z.M)/a3 NA
a= 5.64 x 10-8 cm
Na+ ion is present at edge center, therefore:
2(R++R-)=a
Where
R+ is radius of sodium ion
R- is radius of chloride ion
and
(R++R-) is interionic distance.
(R++R-) =2.82x 10-8 cm