Calculate the enthalpy change for the reaction CH2 = CH2 (g) + H2 (g) → CH3 -CH3 (g). The bond energies of C-C, C-H, H-H and C = C bonds are 83 k cal, 99 k cal, 104k cal and 145 k cal respectively. Share with your friends Share 8 Geetha answered this The given reaction isCH2 = CH2 (g) + H2 (g) → CH3 -CH3 (g)∆H = HR - HP = 4HC-H + HC=C + HH-H - 6HC-H + HC-C = 4 × 99 + 145 + 104 - 6 × 99 + 83 = -32 k Cal 5 View Full Answer