Calculate the enthalpy change for the reaction
CH2 = CH2 (g) + H2 (g) → CH3 -CH3 (g).
The bond energies of C-C, C-H, H-H and C = C bonds are 83 k cal, 99 k cal,
104k cal and 145 k cal respectively.


The given reaction isCH2 = CH2 (g) + H2 (g)  CH3 -CH3 (g)H = HR - HP       = 4HC-H + HC=C + HH-H  - 6HC-H + HC-C       = 4 × 99 + 145 + 104 - 6 × 99 + 83     = -32 k Cal

  • 5
What are you looking for?