calculate the equilibrium constant for the reaction h2 + co2->h2o at 1395k if the equilibrium constant at 1395k for the following are

calculate the equilibrium constant for the reaction h2 + co2->h2o at 1395k if the equilibrium constant at 1395k for the following are 2. Calculate the equilibrium constant for the reaction H2(g) * C02(g) COG) At 1395 K, if the equilibrium constants at 1395 K for the following are 2H20(g) 2c02(g) 2co(g) + 02(g) Kt=2.1xW13 1.4*10-'2

Dear Student, 
As given in the question; for first reaction, we have the following relation
K1=[H2]2  [O2]  [H2O]2  --------------------------1
and for second reaction

​​​​​​
K2= [CO]2  [O2][CO2]2     -------------------------2 
For the reaction given in question H2 + CO2 H2O + CO

We have K = [H2O]  [CO][CO2]  [H2] ----------------------------3 
On dividing equation 2 by equation 1

K2K1  =  [CO]2   [O2][CO2]2   ×   [H2O]2[H2]2   [O2]
On Cancelling O2 from above equation, and on comparing with the equation 3, we have 
K2K1=K2or      K = K2K1= 1.4×10-122.1×10-13=2.58       
Equilibrium constant = 2.58 

Please let me know, if you have any doubts.
Regards

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