Calculate the final volume when the pressure on 1.0 L H₂ changes from 2.20 kPa to 3.00 atm.

[Ans. 7.2 X 10^-3 L]

Dear Student,

Please find below the solution to the asked query:

here the given values are P₁(initial pressure )= 2.20 KPa
  ​                                    ( Final Pressure) P₂ = 3.00atm
                                      (initial volume)V₁= 1.0L
                                     (Final volume)  V₂ =

We know 1KPa = 0.00987 atm
therefore 2.20KPa  = 0.00987 X 2.20
                                = 0.0217 atm

Therefore substituting the value in the presure - volume equation we get

                                                      P₁V₁  = P₂V₂
  
                                                0.0217 x 1 =  3.00 x V₂
                                                0.0217/3    =     V₂
                                     
​ ​                                          Therefore , V₂ = 7.2 X10^-3 L


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