Calculate the following

Calculate the following 5. Calculate : (a) Number of molecules in 6.8 g of hydrogen sulphide (H2S) (b) Number of atoms in 4.8 g of calcium. (c) Number of atoms in 1.62 g of silver

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a>Gram molecular weight(GMW) of H2S=(2+32)=34g
Therefore we know,
No of moles=w(given weight)/GMW=6.8g/34g=0.2 moles of H2S.
1 mole of every substance contains NA molecules(6.023x10^23)
Therefore 0.2 moles of H2S will contain NAx0.2 molecules.

b>Gram atomic weight(GAW) of Ca=40g
Therefore we know,
No of moles=w(given weight)/GAW=4.8g/40g=0.12 moles of Ca.
1 mole of every substance contains NA atoms(6.023x10^23)
Therefore 0.12 moles of Ca will contain NAx0.12 atoms of Ca

c>>Gram atomic weight(GAW) of Ag=107g
Therefore we know,
No of moles=w(given weight)/GAW=1.62g/107g=0.015 moles of Ag.
1 mole of every substance contains NA atoms(6.023x10^23)
Therefore 0.015 moles of Ag will contain NAx0.015 atoms Ca
 
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a>Gram molecular weight(GMW) of H2S=(2+32)=34g Therefore we know, No of moles=w(given weight)/GMW=6.8g/34g=0.2 moles of H2S. 1 mole of every substance contains NA molecules(6.023x10^23) Therefore 0.2 moles of H2S will contain NAx0.2 molecules. b>Gram atomic weight(GAW) of Ca=40g Therefore we know, No of moles=w(given weight)/GAW=4.8g/40g=0.12 moles of Ca. 1 mole of every substance contains NA atoms(6.023x10^23) Therefore 0.12 moles of Ca will contain NAx0.12 atoms of Ca c>>Gram atomic weight(GAW) of Ag=107g Therefore we know, No of moles=w(given weight)/GAW=1.62g/107g=0.015 moles of Ag. 1 mole of every substance contains NA atoms(6.023x10^23) Therefore 0.015 moles of Ag will contain NAx0.015 atoms Ca
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a>Gram molecular weight(GMW) of H2S=(2+32)=34g Therefore we know, No of moles=w(given weight)/GMW=6.8g/34g=0.2 moles of H2S. 1 mole of every substance contains NA molecules(6.023x10^23) Therefore 0.2 moles of H2S will contain NAx0.2 molecules. b>Gram atomic weight(GAW) of Ca=40g Therefore we know, No of moles=w(given weight)/GAW=4.8g/40g=0.12 moles of Ca. 1 mole of every substance contains NA atoms(6.023x10^23) Therefore 0.12 moles of Ca will contain NAx0.12 atoms of Ca c>>Gram atomic weight(GAW) of Ag=107g Therefore we know, No of moles=w(given weight)/GAW=1.62g/107g=0.015 moles of Ag. 1 mole of every substance contains NA atoms(6.023x10^23) Therefore 0.015 moles of Ag will contain NAx0.015 atoms Ca
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Calculate the number of molecules

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Calculate the number of molecules in 6.8 gram of hydrogen sulphide
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