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Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground. ( Given mass of earth= 6 x 10^{24 }kg, Radius of earth = 6.4 x 10^{3} km and G= 6.7 x 10^{-11} Nm^{2 }kg^{-2}.

Here the force of gravitation due to earth is ,

${F}_{G}=\frac{G{M}_{e}m}{{{R}_{e}}^{2}}\phantom{\rule{0ex}{0ex}}=\frac{6\xb77\times {10}^{-11}\times 6\times {10}^{24}\times 1}{{\left(6\xb74\times {10}^{6}\right)}^{2}}\phantom{\rule{0ex}{0ex}}=9\xb781N$

Regards

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