Calculate the half cell potential at 298 K for the rasction, Zn2+ + 2e- ----------> Zn if [Zn2+] = 2M, Eo Zn2 +/Zn= -0.76 V.


a) -0.90 V
b) -0.75 V
c) -0.85 V
d) -0.65 V

Dear Student,

Please find below the solution to the asked query:

For the given half-cell reaction, the Nernst equation can be written as:

EZn2+Zn = EZn2+Zno - 0.0592log1Zn2+EZn2+Zn = -0.76 - 0.0592log12EZn2+Zn = -0.76 - 0.0592-0.301EZn2+Zn = -0.75 V

Hence, the correct answer is option b).

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