Calculate the kinetic energy of an object,if it’s mass is reduced to half

Dear Student,

kinetic energy, K = \frac{1}{2} {mv}^{2} if m' = \frac{m}{2} K' = \frac{1}{2} m' v^{2} K' = \frac{1}{2} \times \frac{m}{2} v^{2} K' = \frac{K}{2} Hence, kinetic energy is also reduced to half .

Regards