calculate the least no of terms of gp 5+10+20+...whose sum would exceed1000000

Sum of GP = a(rn-1)(r-1)Here a = 5, r = 2 So 5(2n-1)(2-1)  1000000
‚Äč(2n-1)  200000
So 2n  200001
So for n  18 equation (1) is satisfying, so least number of term is 18.

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