calculate the longest and shortest wavelengths present in paschen series.

Rydberg’s formula is given as:



Where,
h = Planck’s constant = 6.6 × 10−34 Js
c = Speed of light = 3 × 108 m/s
(n1 and n2 are integers)
For Paschen Series n1= 3
The shortest wavelength present in the Paschen series of the spectral lines is given for values n1 = 3 and n2 = ∞.



Similarly for longest wavelength in the Paschen Series n2 = 4, which will be 1871.8 nm

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