Calculate the Magnetic field induction at the centre of a coil bent in the form of square of side 10cm carrying current of 10A.

Perpendicular distance of the side of the sqaure from the centre is 10/2 = 5 cm=0.05 msince direction of current is same in all sides, therefore net magnetic field will be added upB= 4×μ0I4πrsin 45 - sin(-45))B =  4×μ0I22πrB = 1.414×4π10-7×100.05πB = 113.12×10-6 tesla

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