# Calculate the mass of glucose and water required to make 250g of 25% solution of glucose.

Mass of solution = 250g

Mass % of solution = 25%

Let mass of solute (Glucose) = x g

Mass of solvent (water) = (250 - x) g

Mass of water = 250 - 62.5 = 187.5 g

• 18

Let mass of water be x g.

so,mass of glucose = 25/100*x g.

=x/4 g

Then, mass of solution = (x+x/4)g

=5x/4 g

A/Q,

Mass of solution = 250 g.

or, 5x/4 g = 250 g

or, 5x g = 250 g*4

so, x = 1000 g/5 g

=200

Then, mass of glucose = x/4 g

=200/4 g

=50 g

• -3

concentration of glucose= 25%

m of solute/mass of solution x 100 = 25

m of solute/250 x 100 = 25

m of solute = 25/100 x 250 =62.5 g

• 14

Let mass of water be x g

So, mass of glucose = 25% of x g

= 25/100*x g

=x/4 g

A/Q,

Mass of solution = 250 g

or, (x+x/4)g = 250 g

or, 5x/4 g = 250 g

or, 5x g = 250 g*4

so,x = 1000g/5g

=200

Then,

mass of water = x g

=200g

& mass of glucose = x/4 g

=200/4 g

=50 g

• -3

mass of solute =x

mass of solvent =y

massof solution=x+y

concentration =x/x+y*100

25=x/x+x/y*100

25/100=x/y

1/4=x/y

interpret the  result

x=a(let)

y=4a(let)

mass of solution=250g

x+y=250g

a+4a=250g

5a=250g

a=250g/5

a=50g

mass of solute(glucose)=a=50g

mass of solvent (water)=4a=4*50g=200g

• -3

let the mass of glucose b x.

so mass of solution=x+250

concentration of glucose

25%  =  x

----------*100

x+250

after that solve urself.

its easy .

sorry i couldnt .as i got to go

• -7
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