Calculate the mass of glucose and water required to make 250g of 25% solution of glucose.

Let mass of water be x g.

so,mass of glucose = 25/100*x g.

                                    =x/4 g 

Then, mass of solution = (x+x/4)g

                                            =5x/4 g

A/Q,

Mass of solution = 250 g.

or, 5x/4 g = 250 g

or, 5x g = 250 g*4

so, x = 1000 g/5 g

         =200

Then, mass of glucose = x/4 g

                                           =200/4 g

                                           =50 g                              

concentration of glucose= 25%

m of solute/mass of solution x 100 = 25

m of solute/250 x 100 = 25

m of solute = 25/100 x 250 =62.5 g

Let mass of water be x g

So, mass of glucose = 25% of x g

                                          = 25/100*x g

                                         =x/4 g

A/Q,

Mass of solution = 250 g

or, (x+x/4)g = 250 g

or, 5x/4 g = 250 g

or, 5x g = 250 g*4

so,x = 1000g/5g

         =200

Then,

             mass of water = x g 

                                        =200g

         & mass of glucose = x/4 g

                                             =200/4 g

                                             =50 g

mass of solute =x

mass of solvent =y

massof solution=x+y

concentration =x/x+y*100

25=x/x+x/y*100

25/100=x/y

1/4=x/y

interpret the  result

x=a(let)

y=4a(let)

mass of solution=250g

x+y=250g

a+4a=250g

5a=250g

a=250g/5

a=50g

mass of solute(glucose)=a=50g

mass of solvent (water)=4a=4*50g=200g