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calculate the no. of atoms in 0.8 g of iron. (Fe=56)

We have, 0.8 g of iron.

We are given, atomic mass of iron = 56u

Therefore, molar mass of iron = 56g

No. of moles = Given mass / Molar mass

                   = 0.8 / 56 = 0.014(Approx.)

So number of particles = 0.014 x 6.022 x 1023

                                 =  0.084308 x 1023

                                 = 8.4308 x 1021

                                     

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1 mole of ferris atom = 56 grams 
1 mole of ferris atom = 6.022 * 10 to the power 23 atoms
=> 56 grams of ferris atoms = 6.022 * 10 23
=> 1 gram of ferris atom = 6.022 * 1023 / 53
=> 0.8 grams of ferris atoms = ( 6.022 * 1023 / 53 ) * 0.8
                                                     = 9089811320754716981132.075 atoms

( Whew, the calculation took heck of a time )

HOPE IT HELPS
REGARDS,
MEHERWAN

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To calculate no. of atoms we use formula-

no. of atoms=(given mass/gram atomic mass)*avogadro's no.

no. of atoms=( 0.8/56)*6.022*10 raise to power 23

=.08628*10 raise to power 22

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