calculate the normality of a solution containing 5g NaOH in 450 ml solution.
Normality = No. of equivalents / Volume of solution (L)
No. of equivalents = Mass / Equivalent mass
Equivalent weight or mass = Molar mass / n-factor
n-factor for NaOH = 1
Equivalent weight = Molar mass
No. of equivalents = 5/40 = 1/8 equivalents
Normality = (1/8) /0.450 = 0.2777 N or 5/18 N
No. of equivalents = Mass / Equivalent mass
Equivalent weight or mass = Molar mass / n-factor
n-factor for NaOH = 1
Equivalent weight = Molar mass
No. of equivalents = 5/40 = 1/8 equivalents
Normality = (1/8) /0.450 = 0.2777 N or 5/18 N