# Calculate the number of atoms in a cubic type unit cell having one atom at each corner of the cube and two atoms on one of its body diagonal

Please find below the solution to the asked query:

Since each corner atom is shared between eight adjacent unit cells. Therefore, only 1/8th of an atom is what actually belongs to a unit cell. Since, the simple cubic unit cell has eight corners, the total number of atoms in one unit cell = $8\times \frac{1}{8}=1atom$

As the questions says there are two atoms on one of its body diagonal, then total number of atoms in body diagonal of a simple cubic unit cell = 2 atoms.

So, total number of atoms in this cubic unit cell = 1 + 2 = 3 atoms.

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