Calculate the number of atoms in a cubic type unit cell having one atom at each corner of the cube and two atoms on one of its body diagonal

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Please find below the solution to the asked query:

Since each corner atom is shared between eight adjacent unit cells. Therefore, only 1/8th of an atom is what actually belongs to a unit cell. Since, the simple cubic unit cell has eight corners, the total number of atoms in one unit cell = 8×18=1 atom

As the questions says there are two atoms on one of its body diagonal, then total number of atoms in body diagonal of a simple cubic unit cell = 2 atoms.

So, total number of atoms in this cubic unit cell = 1 + 2 = 3 atoms.

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