Calculate the number of coulombs of electricity passed to liberate 200ml of H2gas at 25 degree celcius 760mm - Chemistry -

Question

Calculate the number of coulombs of electricity passed to liberate
200ml of H2 gas at 25 degree celcius & 760mm
pressure
In ans it is given that:
Wt of H2=MPV
RT
=2*760/760*200/1000
0 0821*298
But how 2*760/760*200/1000 came
please explain

Geetha · Accepted Answer

According to Faraday's first lawW=ZQWhere W is the amount of substance liberated or depositedQ = Number of coulombsZ= electrochemical equivalent = molar massn × faraday = 22 × 96500According to Ideal gas equationPV= nRTPV = W2M2 RTW2 = M2PVRTM2 = molecular mass of the hydrogen =2P= pressure in atm =1 atm [ since 1 atm = 760 mm i
e, 760760]V- volume in litre = 0
2 L  2001000R= gas constant = 0
0821 L atmT = temperature = 298 KSoW2 = 2 × 1 × 0
20 0821 ×298 = 0
01635 gAccording to faraday lawW= ZQ0
01635 = 22 × 96500 × QQ= 1577
71 coulombs

Calculate the number of coulombs of electricity passed to liberate 200ml of H2 gas at 25 degree celcius & 760mm pressure. In ans. it is given that: Wt of H2=MPV RT =2*760/760*200/1000 0.0821*298 But how 2*760/760*200/1000 came. please explain.

Calculate the number of coulombs of electricity passed to liberate 200ml of H₂ gas at 25 degree celcius & 760mm pressure.
In ans. it is given that:
Wt of H₂=MPV
RT
=2760/760200/1000
0.0821298
But how 2760/760*200/1000 came.
please explain.