Calculate the number of coulombs required for oxidation of 1 mole of water to oxygen.
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Please find below the solution to the asked query:
The oxidation of water to oxygen is a 4-electron process:
2 H2O (l) → O2 (g) + 4 H+ (aq) + 4 e−
From the above reaction we can say that, 4 moles of electron is required to oxidise 2 moles of water, hence for 1 mole of water we require 2 moles of electrons. As we know that, 1 mole of electrons has the charge of 96487 C , then in 2 mole of electrons we have = 2 x 96487 = 192974 C.
Hence, we require 192974 Coulomb of charge to oxidise 1 mole of water to oxygen.
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Please find below the solution to the asked query:
The oxidation of water to oxygen is a 4-electron process:
2 H2O (l) → O2 (g) + 4 H+ (aq) + 4 e−
From the above reaction we can say that, 4 moles of electron is required to oxidise 2 moles of water, hence for 1 mole of water we require 2 moles of electrons. As we know that, 1 mole of electrons has the charge of 96487 C , then in 2 mole of electrons we have = 2 x 96487 = 192974 C.
Hence, we require 192974 Coulomb of charge to oxidise 1 mole of water to oxygen.
Hope this information will clear your doubts about Electrochemistry.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Best Wishes !