calculate the number of molecules present in a drop of chloroform (CHCl3) weighing 0.0239g.
molecuar mass of CHCl3 = 12 + 1 +3 x 35.5 = 119.5g
119.5g contain = 6.022 x 10^23 molecules
thereforce, 0.0239g contain = 6.022 x 10^23 x 0.0239 / 119.5
= 12.044 x 10^19 molecules