calculate the numbers of atom of C and O in 72.5g isopropanol C3H7OH (MOLAR MASS 60)

1 mole of isopropanol contain 3 moles of C and 1 mole of oxygen.
Molar mass of isopropanol = 60 g
Then 60 g of isopropanol contain 3 moles of  C and 1 mole of O.
Therefore 72.5 g of isopropanol would contain :
Moles of C = 3  / 60 g mol-1  x 72.5 g  = 3.625 moles of C
Moles of O = ​1 / 60 g mol-1 x 72.5 g  = 1.208 moles of O

Number of carbon atoms = ​3.625 x 6.022 x 1023
                                        = 2.18 x 1024 atoms of C
Number of Oxygen atoms = ​1.208 x 6.022 x 1023
                                        = 7.27 x 1023 atoms of O​

 

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