calculate the numbers of atom of C and O in 72.5g isopropanol C3H7OH (MOLAR MASS 60)
1 mole of isopropanol contain 3 moles of C and 1 mole of oxygen.
Molar mass of isopropanol = 60 g
Then 60 g of isopropanol contain 3 moles of C and 1 mole of O.
Therefore 72.5 g of isopropanol would contain :
Moles of C = 3 / 60 g mol-1 x 72.5 g = 3.625 moles of C
Moles of O = 1 / 60 g mol-1 x 72.5 g = 1.208 moles of O
Number of carbon atoms = 3.625 x 6.022 x 1023
= 2.18 x 1024 atoms of C
Number of Oxygen atoms = 1.208 x 6.022 x 1023
= 7.27 x 1023 atoms of O
Molar mass of isopropanol = 60 g
Then 60 g of isopropanol contain 3 moles of C and 1 mole of O.
Therefore 72.5 g of isopropanol would contain :
Moles of C = 3 / 60 g mol-1 x 72.5 g = 3.625 moles of C
Moles of O = 1 / 60 g mol-1 x 72.5 g = 1.208 moles of O
Number of carbon atoms = 3.625 x 6.022 x 1023
= 2.18 x 1024 atoms of C
Number of Oxygen atoms = 1.208 x 6.022 x 1023
= 7.27 x 1023 atoms of O