Calculate the percentage of
[a] Water of crystallization in CuSO4.5H2O
[B] Potassium in K2CO3
[c] Oxygen in 22g of CO2
[D] Hydrogen in 36g of water
a) Molar mass of CuSO4.5H2O =250
mass of water of crystallization = 5 x 18 = 90
% = 90/250 x 100 = 36 %
b) Molar mass of K2CO3 = 138
Mass of K = 2 x 39 = 78
% = 78/138 x 100 = 56%
c) Molar mass of CO2 = 44g
Oxygen in 44 gram CO2 = 32 g
⇒Oxygen in 22 g CO2 = 16 g
% = 16/22 x 100 = 72%
d) Molar mass of water = 18 g
Hydron in 18 gram H2O = 2 g
36 gram of water (H2O) will contain 4 gram of H
% = 4/36 x 100= 11 %
mass of water of crystallization = 5 x 18 = 90
% = 90/250 x 100 = 36 %
b) Molar mass of K2CO3 = 138
Mass of K = 2 x 39 = 78
% = 78/138 x 100 = 56%
c) Molar mass of CO2 = 44g
Oxygen in 44 gram CO2 = 32 g
⇒Oxygen in 22 g CO2 = 16 g
% = 16/22 x 100 = 72%
d) Molar mass of water = 18 g
Hydron in 18 gram H2O = 2 g
36 gram of water (H2O) will contain 4 gram of H
% = 4/36 x 100= 11 %