calculate the ph of 0.01 M Al(OH)3 solution

Dear Student

As three OH- are formed by 1 molecule of Al(OH)3.
As concentration of Al(OH)3 is 0.01 M, so, concentration of OH- = 0.03 M
pOH = -log[OH-]
pOH = -log (0.03)
pOH = 1.52

As pH + pOH = 14
So, pH = 14 - 1.52 = 12.48

 

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