Login

Calculate the pH of a solution which contains 9.9 ml of 1 M HCl and 100 ml of 0.1 M NaOH​

Dear Student,

Kindly refer to the link for similar query,

https://www.meritnation.com/ask-answer/question/determine-the-ph-of-a-solution-prepared-by-mixing-50-ml-o/chemical-and-ionic-equilibrium/9815135

Hope this information clears your doubts about the topic.

Keep asking!!

Regards

  • -2
View Full Answer
Dunno  :( sorry
  • -2
NaOH reacts with HCl :?
NaOH + HCl ? NaCl + H2O?
1 mol NaOH reacts with 1 mol HCl?

Mol HCl in 9.9mL of 1.0M solution = 9.9/1000*1.0 = 0.0099 mol HCl?
Mol NaOH in 100mL of 0.1M solution = 100/1000*0.1 = 0.01 mol NaOH?
On mixing the 0.0099 mol HCl will be neutralised and 0.01 - 0.0099 = 1*10^-4 mol NaOH dissolved in 109.9mL solution?
Molarity of NaOH solution = (1*10^-4) / 0.1099 = 9.099*10^-4M?
pOH = -log ( 9.099*10^-4)?
pOH = 3.04?
pH = 14.00 - pOH?
pH = 14.00 - 3.04?
pH = 10.96
  • 2
What are you looking for?