calculate the potential at a zinc zinc ion electrode in which the zinc ion activity is 0.001M Share with your friends Share 8 Geetha answered this According to Nernst equationEZn = EZn/Zn2+0 - 0.0591n log 1oxidised speciesHere the cell is with only oxidised species Zn →→ Zn2+ + 2 e-EZn = -0.76 - 0.05912 log 10.001 = -0.8487 V 23 View Full Answer