calculate the potential at a zinc zinc ion electrode in which the zinc ion activity is 0.001M

According to Nernst equationEZn = EZn/Zn2+0 - 0.0591n log 1oxidised speciesHere the cell is with only oxidised species Zn  Zn2+ + 2 e-EZn = -0.76 - 0.05912 log 10.001     = -0.8487 V

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