Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Given,

pH = 10

Now,

pH = -log[H+]

Therefore,

[H+] = 10-10 mol/L

 

The reaction involved:

According to Nernst equation:

Hence potential of hydrogen electrode = - 0.591 V

  • 94

Hello,

For hydrogen electrode, , it is given that pH = 10

[H+] = 10−10 M

Now, using Nernst equation:

 

= −0.0591 log 1010

= −0.591 V.

 

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