CALCULATE THE RATIO OF MOLECULES PRESENT IN 6.6g OF CO₂ AND 3.2G OF SO₂?(C=12U,O=16U,S=32U)

The molar mass of CO₂ is calculated as follows

molar mass of CO₂ = molar mass of carbon + 2 X (molar mass of oxygen)

= (12 + 16 X 2)g

= 44g

Thus, the molar mass of CO₂ is 44g. This means that there are 6.022 X 10²³ molecules of CO₂ in 44g of CO₂. So

44g of CO₂ =  6.022 X 10²³ molecules of CO₂ 

1g of  CO₂ =  (6.022 X 10²³ / 44) molecules of CO₂

6.6g of CO₂ =  (6.022 X 10²³ X 6.6) / 44  molecules of CO₂

= 9.033 X 10²² molecules of CO₂

Similarly, we can calculate the molar mass of SO₂. It comes out to be 64g. Thus

64g of SO₂ = 6.022 X 10²³ molecules of SO₂

1g of SO₂ = (6.022 X 10²³ / 64) molecules of SO₂

3.2g of SO₂ = (6.022 X 10²³ X 3.2) / 64 molecules of SO₂

= 3.011 X 10²² molecules of SO₂

Thus

Number of molecule in 6.6g of CO₂ / Number of molecules in 3.2g of SO₂ = (9.033 X 10²²) / (3.011 X 10²²)

= 3

Thus, the ratio comes out to be 3 : 1.