CALCULATE THE RATIO OF THE SHORTEST WAVELENGTHS OF THE LYMAN AND BALMER SERIES OF THE SPECTRA - Physics - Atoms

Question

CALCULATE THE RATIO OF THE SHORTEST WAVELENGTHS OF THE LYMAN AND
BALMER SERIES OF THE SPECTRA?

Vara · Accepted Answer

Shortest wavelength in Lyman series:1λ=R112-1∞λ=1R   =11
097×107   =9
11×10-8 mShortest wavelength in Balmer series:The highest energy corresponding to shortest wavelength is,△E=-13
6 eV 1∞-14        =3
4 eV         =3
4×1
6×10-19 J         =5
44×10-19 JShortest wavelength is,λ=hc△E   =6
6×10-343×1085
44×10-19    =365×10-9 mRatio of Shortest wavelength in Lyman series and Balmer series:Ratio =9
11×10-8365×10-9           =0
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CALCULATE THE RATIO OF THE SHORTEST WAVELENGTHS OF THE LYMAN AND BALMER SERIES OF THE SPECTRA?