calculate the total molarity and normality of all the ions present in a solution containing 0.1M CuSO4 and 0.1M Al2(SO4)3

1. Molarity is same for all the ions in a homogeneous solution.
Normality = Molarity $×$ Charge(or valency)

2. Molarity and Normality of the ions in 0.1M CuSO4  is :

Molarity of Cu2+ =  0.1 M                       Normality of Cu2+ = 2 $×$0.1= 0.2 M
Molarity of SO42- = 0.1 M                        Normality of SO42- = 2 $×$0.1 = 0.2 M

3. Molarity and Normality of the ions in 0.1M Al2(SO4)3 is :

Molarity of Al3+ = 0.1 M                           Normality of Al3+ = 3 $×$ 0.1 = 0.3 M
Molarity of SO42- = 0.1 M                        Normality of SO42- = 2 $×$0.1 = 0.2 M

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