# calculate the total no of ions present in 117g  of   NaCl

1. 1 mole of NaCl has 2 moles of ions, 1 mole of Na+ and 1 mole of Cl-.

2. Number of moles of molecules in 117 g of NaCl =
3. Number of moles of ions = 2(2) = 4 moles of ions.

1 mole = 6.023 $×$1023

So, total number of ions = 4(​ 6.023 $×$1023)
= 2.41 ​$×$1024 ions.

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t refer to any of the links ..plz solve it its very urgent

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