calculate the volume occupied by 66.0 g of carbon dioxide (co₂) under N.T.P conditions?

Molar mass of CO₂ = 44 g mol-1
Volume occupied by 1 mole of gas at NTP is 24.8 L
44 g of CO₂ occupies = 24.8 L
66 g of CO₂ occupies = $\frac{24.8}{44}\times 66$ = 37.2 L