calculate the volume of  0.05 KMno4 solution required to oxidised completely 2.70 g of oxalic acid in acidic solution​

Dear Student,


To calculate number of moles of KMnO4 required to oxidised completely 2.70 g of oxalic acid in acidic medium.

Molecular weight of H2C2O4.2H20 = 126 g
Number of moles of oxalic acid = Mass of oxalic acidMolar mass =2.70 126  =0.0214 g
5 moles of oxalic acid is oxidised by 2 moles of KMnO4So, 0.021 moles of oxalic acid is oxidised by 25×0.021 moles of KMnO4 =0.00857
To calculate volume of 0.05 M  KMnOsolution :
0.05 moles of KMnO are contained in 1000 ml of the solutionSo. 0.00857 moles of KMnO are contained = 1000 0.05×0.00857 ml =171.42 ml

 

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