Calculate the volume of hydrogen required for complete hydrogenation of 0.25 dm3 of ethyne at STP.

Hydrogenation of ethyne complete in 2 process:- 1) C2H2 + H2 = C2H4 2) C2H4 + H2 = C2H6 Now add this, C2H2 + H2 = C2H6 Hence, for 1 mole hydrogenation of ethyne 2 mole of H2 is require So, 22.4 L hydrogenation of C2H2, 2 × 22.4 L H2 is require So, 0.25 L, hydrogenation of C2H2 2×0.25L of H2 is require Hence 0.5 L OR 0.5 dm^3 volume of H2 is require Note 1 L = 1dm^3
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