calculate the volume of oxygen required for the complete combustion of 8.8 g of propane
Solution-
The balanced equation of Combustion of propane is-
C3H8 + 5O2 → 3CO2 + 4H2O
The molecular mass of propane = 44 gm
The volume of 5 O2 at STP = 5 22.4 = 112 L
So, 44g of propane requires 112 L of oxygen for complete combustion.
8.8 gm of propane requires oxygen for combustion = = 22.4 L
The balanced equation of Combustion of propane is-
C3H8 + 5O2 → 3CO2 + 4H2O
The molecular mass of propane = 44 gm
The volume of 5 O2 at STP = 5 22.4 = 112 L
So, 44g of propane requires 112 L of oxygen for complete combustion.
8.8 gm of propane requires oxygen for combustion = = 22.4 L