calculate the volume of oxygen required for the complete combustion of 8.8 g of propane

Solution-

The balanced equation of Combustion of propane is-

C3H8 + 5O2  3CO2 + 4H2O

The molecular mass of propane = 44 gm
The volume of  5 O2 at STP = 5 × 22.4 = 112 L
So, 44g of propane requires 112 L of oxygen for complete combustion.

 8.8 gm of propane requires oxygen for combustion = 11244×8.8 = 22.4 L

  • 0
What are you looking for?