Calculate the wavelength of the spectral line obtained in the spectrum of li2+ ion the transition takes place between two levels whose sum is 4 And difference is 2

x+ y = 4. {x= n1 & y= n2}
x-y = 2
2x = 6
x =3
y=1

1/wavelength = v` , wave no.

v` = R (Z)^2 * [1/y - 1/x]
{R is rydbergs cnstnt...
z = atomic no.
y is taken first as electron move from lower to higher level}

v` = [109677 * (3)^2 * (1/1-1/3) ] cm^(-1)
{ z = 3}

v` = 109677* 9* 2/3
= 109677 * 6
= 658062 cm^(-1)

wavelength = 1/v`
= 1/ 658062 cm
it can also be converted to m
hop it hlpd
  • -33
You can improve calculations
  • -6
Calculate the wavelength of the spectral line obtained in the spectrum of Li2+ ion the trasition takes place between two levels whose sum is 4 and difference is 2
  • -2
calculate the wave length of spectral line obtained in spectrum of li2+ ions when transition takes place between two levels whose difference is 2 and sum is 4
  • 2

Let the transition occurs in between the levels n1​ and n2​. Thus, if then given
n1​+n2​=4
n2​−n1​=2        ∴n2​=3,n1​=1
Therefore, λ1​=R​×Z2[121​−321​]     (∵Z=3 for Li)
=109678×32×[8/9]
∴λ=1.14×10−6cm

  • -1
Calculate the wavelength of the spectral line obtained in the spectrum of Li2+ ion where the transition takes place between two levels whose sum is 4 and difference is 2.
  • 0
What are you looking for?