Calculate the wavelength of the spectral line obtained in the spectrum of li2+ ion the transition takes place between two levels whose sum is 4 And difference is 2
x+ y = 4. {x= n1 & y= n2}
x-y = 2
2x = 6
x =3
y=1
1/wavelength = v` , wave no.
v` = R (Z)^2 * [1/y - 1/x]
{R is rydbergs cnstnt...
z = atomic no.
y is taken first as electron move from lower to higher level}
v` = [109677 * (3)^2 * (1/1-1/3) ] cm^(-1)
{ z = 3}
v` = 109677* 9* 2/3
= 109677 * 6
= 658062 cm^(-1)
wavelength = 1/v`
= 1/ 658062 cm
it can also be converted to m
hop it hlpd
x-y = 2
2x = 6
x =3
y=1
1/wavelength = v` , wave no.
v` = R (Z)^2 * [1/y - 1/x]
{R is rydbergs cnstnt...
z = atomic no.
y is taken first as electron move from lower to higher level}
v` = [109677 * (3)^2 * (1/1-1/3) ] cm^(-1)
{ z = 3}
v` = 109677* 9* 2/3
= 109677 * 6
= 658062 cm^(-1)
wavelength = 1/v`
= 1/ 658062 cm
it can also be converted to m
hop it hlpd