calculation of pure and hybrid orbitals ratio of benzene

Dear student,

In Benzene each carbon is sp2 hybridizes. 2s and 2p orbitals of carbon  participate in hybridization to form 3 sp2 hybrid orbitals but its 1s orbital remain unhybridized.

Hydrogen has only one 1s orbital and the single orbital can not undergo hybridization, so it remains in pure form.

thus there are 18 hybridized orbitals(3 from each carbon) and 12 pure orbitals( 1 from each carbon and 1 from each hydrogen) in a benzene ring.

Hence the ratio of pure and hybridized orbitals is 3:2.

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards
 

  • 1
The answer is

12.4 Molecular Orbitals of Benzene. Benzene has?six?molecular orbitals that form a delocalized ? system; three of benzene's molecular orbitals are bonding and each has two electrons; three are antibonding, and they are vacant.
  • 2
What are you looking for?