Dear student,Assuming that the question is:Whether 3+5=8It is actually not Let verify it:Method 1:We know that, 3=1 73 , 5=2 23 , 8=2 83So, LHS: 3+5=1 73+2 23=3 96RHS: 8=2 83Therefore, LHS≠RHS Method 2:Square both sides:3+52=82LHS:(a+b)2=a2+b2+2ab3+52=3+5+215=8+215RHS:82=8As, by comparison we can say that,8+215>8So, LHS is actually greater than RHS rather than both to be equal Regards

Can ?3+ ?5 = ?8

Dear student, Assuming that the question is : Whether \sqrt{3} + \sqrt{5} = \sqrt{8} It is actually not . Let verify it : Method 1 : We know that, \sqrt{3} = 1.73, \sqrt{5} = 2.23, \sqrt{8} = 2.83 So, LHS : \sqrt{3} + \sqrt{5} = 1.73 + 2.23 = 3.96 RHS : \sqrt{8} = 2.83 Therefore, LHS \neq RHS . Method 2 : Square both sides : {(\sqrt{3} + \sqrt{5})}^{2} = {(\sqrt{8})}^{2} LHS : {(a + b)}^{2} = a^{2} + b^{2} + 2 ab {(\sqrt{3} + \sqrt{5})}^{2} = 3 + 5 + 2 \sqrt{15} = 8 + 2 \sqrt{15} RHS : {(\sqrt{8})}^{2} = 8 As, by comparison we can say that, 8 + 2 \sqrt{15} > 8 So, LHS is actually greater than RHS rather than both to be equal . Regards

View Full Answer