Can any one please show the formula and procedure of these

Dear Student
14.
$$\begin{gathered} Here resis\tan ce along branches are connected in parallel \\ Net resis\tan ce \\ R =\frac{1}{{\displaystyle \frac{1}{60}}+{\displaystyle \frac{1}{15+5}}+{\displaystyle \frac{1}{10}}} =\frac{1}{{\displaystyle \frac{1}{60}+\frac{1}{20}+\frac{1}{10}}} \\ R =\frac{60\times 20\times 10}{200 +600+1200} =\frac{12000}{2000} =6Ohm \\ So \\ V = IR =1\times 6 = 6V \\ Now voltage drop along each branch is same \\ So \\ {I}_{60} =\frac{V}{R_{60}} =\frac{6}{60} =0.1A \end{gathered}$$
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