can anybody expalin the justification of the perpendicular bisector....???

its really confusing..!!!

:(

Hi!

In the video given in this lesson, RS is justified as the perpendicular bisector of PQ. This means it has been proved that RS is perpendicular to PQ and also RS bisects PQ. For this, I have considered O as the intersection of PQ and RS.

In the first step, I have shown you ∆PSR ≅ ∆PSR using SSS congruency rule. By doing so, I got ∠PRS = ∠QRS. (C.P.C.T.)

 

In the next step I have used ∠PRS = ∠QRS to prove ∆PRO ≅ ∆QRO using SAS congruency rule.

Here, I got OP = OQ (C.P.C.T.). This implies that RS bisects PQ. Also, I got ∠ROP = ∠ROP (C.P.C.T.). But these angles are linear pairs. By solving few more steps I got ∠ROP = ∠ROP = 90°. This shows that RS is perpendicular to PQ.