can anyone explain multiplication of 2-digits,using vedic maths

*actually

what is this vedic maths

eg 12*32

12

32  

multiply 2 and 2  = 4 this is the last digit of ur answer

then crossmultiply and add

1*2 + 2*3 = 8 second last digit of ur answer

then cut out the left side i.e 2 and 2 then multiple the remaining just like that i.e

1*3 = 3 this is the first digit of ur answer

therfore ur answer is 384

u can use this method to multiply n digit nos. but it gets a slight complicated.

 eg 12*32

12

32

multiply 2 and 2 = 4 this is the last digit of ur answer

then crossmultiply and add

1*2 + 2*3 = 8 second last digit of ur answer

then cut out the left side i.e 2 and 2 then multiple the remaining just like that i.e

1*3 = 3 this is the first digit of ur answer

therfore ur answer is 384

u can use this method to multiply n digit nos. but it gets a slight complicated.

y ur multiply wid 2.

really i don't understood that problem.so once again explain d problem with clear explanation.

plz help me.

For eg 99 *98.

-The closest multiple of 10 to 99 and 98 is 100.

-So we take the difference of both nos. from 100.

 -        99     98

          -1      -2

-Then we multiply the differences :            02

and place them in the units place.

Then we cross-add 99 and -2 or 98 and -1

and place them in thethousands and hundreds place.

-Hence we get 9702.

eg 12*32

12

32

multiply 2 and 2 = 4 this is the last digit of ur answer

then crossmultiply and add

1*2 + 2*3 = 8 second last digit of ur answer

then cut out the left side i.e 2 and 2 then multiple the remaining just like that i.e

1*3 = 3 this is the first digit of ur answer

therfore ur answer is 384

u can use this method to multiply n digit nos. but it gets a slight complicated.