# Can anyone help me with the 17th question

Dear Student,

$Principal,P=Rs.3000\phantom{\rule{0ex}{0ex}}Amount,A=Rs.3993\phantom{\rule{0ex}{0ex}}Time,n=3years\phantom{\rule{0ex}{0ex}}Lettherateofinterestber\%p.a..\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Wheninterestiscompoundedannually:\phantom{\rule{0ex}{0ex}}A=P{\left(1+\frac{r}{100}\right)}^{n}\phantom{\rule{0ex}{0ex}}3993=3000{\left(1+\frac{r}{100}\right)}^{3}\phantom{\rule{0ex}{0ex}}\frac{3993}{3000}={\left(\frac{100+r}{100}\right)}^{3}\phantom{\rule{0ex}{0ex}}\frac{1331}{1000}={\left(\frac{100+r}{100}\right)}^{3}\phantom{\rule{0ex}{0ex}}{\left(\frac{11}{10}\right)}^{3}={\left(\frac{100+r}{100}\right)}^{3}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Since,exponentsarethesame,wecancomparethebases:\phantom{\rule{0ex}{0ex}}\frac{11}{10}=\frac{100+r}{100}\phantom{\rule{0ex}{0ex}}\frac{11\times 100}{10}=100+r\phantom{\rule{0ex}{0ex}}110=100+r\phantom{\rule{0ex}{0ex}}r=110-100\phantom{\rule{0ex}{0ex}}r=10\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Hence,rateofinterest=10\%p.a.$

Regards

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