Can anyone please answer these questions..
Question 17
(a) ( l) Account for the following /Explain why:
(i) Oxygen molecule is diatomic whereas Sulphur molecule is polyatomic.
(ii) SF6 is exceptionally stable, SH6 does not exist.
(iii) Bond angle in PH4' is higher than that in PH3
(2) Comment on the nature of S-O bonds formed in SO2 molecule.
OR
(b) Describe manufacture of H2SO4 by contact process.
(i) Why does NO2 dimerise.
(ii) What happens when H3PO3is heated
(iii) Give reactions of copper metal with dil. and conc. Nitric acid.
Dear student,
a) 1)i)Due to presence of p orbital , O ca form pπ - pπ bond .This makes the molecule O2 stable.
a) 1)i)Due to presence of p orbital , O ca form pπ - pπ bond .This makes the molecule O2 stable.
ii) In SF6, F being highly electronegative will make S to loose 6 electron i.e. maximum valence electron. But H being least electronegative will not be able to do so. So SF6 exists but SH6 does not.
iii) In PH3 , there is a lone pair of electron which causes lone pair - bond pair repulsion and ultimately decrease bond angle . As in PH4+ , the lone pair is consumed and the repulsion decreases and the bond angle increases.
2) The electronic configuration of S is 1s2 2s2 2p6 3s2 3p4. In the formation of SO2 , one electron from 3p orbital goes to the 3d orbital and S undergoes sp2 hybridization. Two of these orbitals form sigma bonds with two oxygen atoms and the third contains a lone pair. p-orbital and d-orbital contain an unpaired electron each. One of these electrons forms pπ- pπ bond with one oxygen atom and the other forms pπ- dπ bond with the other molecule. So this has bent structure.
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iii) In PH3 , there is a lone pair of electron which causes lone pair - bond pair repulsion and ultimately decrease bond angle . As in PH4+ , the lone pair is consumed and the repulsion decreases and the bond angle increases.
2) The electronic configuration of S is 1s2 2s2 2p6 3s2 3p4. In the formation of SO2 , one electron from 3p orbital goes to the 3d orbital and S undergoes sp2 hybridization. Two of these orbitals form sigma bonds with two oxygen atoms and the third contains a lone pair. p-orbital and d-orbital contain an unpaired electron each. One of these electrons forms pπ- pπ bond with one oxygen atom and the other forms pπ- dπ bond with the other molecule. So this has bent structure.
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Regards