can anyone proof this theoram and tell me?
'IF TWO TRINGLES OF EQUAL AREAS LIE ON THE SAME BASE , THEN THEY SHOULD LIE BETWEEN THE SAME PARALLELS'.
Dear Student!
The theorem "Triangles having the same base and equal areas lie between the same parallels" can be proved as,
Given: ΔPQR and ΔSQR such that ar (ΔPQR) = ar (ΔSQR).
Construction: Draw PL and SM perpendicular to QR
To prove: PS || QR
Hence, PS || QR
Hope! You got the answer.
Cheers!