Can I get the answer of this question

Dear Student,

Diameter of a circular track, d = 200 m

Radius of the track, r =

Circumference = 2πr = 2π (100) = 200π m

In 40 s, the given athlete covers a distance of 200π m.

In 1 s, the given athlete covers a distance =

The athlete runs for 2 minutes 20 s = 140 s

∴Total distance covered in

The athlete covers one round of the circular track in 40 s. This means that after every 40 s, the athlete comes back to his original position. Hence, in 140 s he had completed 3 rounds of the circular track and is taking the fourth round.

He takes 3 rounds in 40 × 3 = 120 s. Thus, after 120 s his displacement is zero.

Then, the net displacement of the athlete is in 20 s only. In this interval of time, he moves at the opposite end of the initial position. Since displacement is equal to the shortest distance between the initial and final position of the athlete, displacement of the athlete will be equal to the diameter of the circular track.

∴ Displacement of the athlete = 200 m

Distance covered by the athlete in 2 min 20 s is 2200 m and his displacement is 200 m.


Regards

 

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4298 m
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2min+20 sec= 140 seconds. Radius = 100 M In 40 sec distance covered = 2π*(100)= 200π (i). so in 140 sec distance covered= 200π*140/40= 2200 M ii).In 40*3sec = 120 sec, 3 rotations would be completed ie displacement after 120 sec= 0, as athelete comes to start point after 3 rotations. Now in further 20 sec (to make it 140 sec), it will complete half rotation ie will reach a point diametrically opposite to start point. So displacement = dia of circle= 200 M
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458m
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458m
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