Can someone please answer this?

Dear Student,

Number of times 2 or more tails occur n(A):- 20 + 68 = 88
Total number of tosses n(T) = 200.

Probability of at least 2 tails = $\frac{n\left(A\right)}{n\left(T\right)}=\frac{88}{200}=\frac{11}{25}= 0.44$

Regards