# can the sum of interior angles of a polygon be 4300 justify

Let the number of sides of the polygon whose sum of interior angles is 4300 be n

now, sum of interior angles of a polygon is given by (n-2) * 180 //where n = number of sides//

so, (n-2) * 180 = 4300

or n-2 = 4300/180 = 23.88

or n = 23.88 + 2 = 25.88

but, number of sides cannot be a decimal number,

so, sum of interior angles of a polygon cannot be 4300