#
Can you answwr this question ?

Q. $\u25b3$LMN is an isosceles right-angled triangle. If the square of the hypotenuse of $\u25b3$LMN is 32 $c{m}^{2}$, then what is the length of each of the two equal sides?

LN)

^{2}= 32 cm (Hypotenuse

^{2})

And LM and MN are equal as is an isosceles right angled triangle.

Let us assume both LM and LN to be 'y'

According to Pythagoras Theorem, we can tell that:

(perpendicular

^{2}) + (base

^{2}) = (hypotenuse

^{2})

So, here ,

(LM)

^{2}+ (MN)

^{2}= (Hypotenuse

^{2}) = 32 cm

^{2}

y

^{2}+ y

^{2}= 32 cm

^{2}

=> 2(y

^{2}) = 32 cm

^{2}

=> y

^{2}= 32 cm

^{2}/ 2 = 16 cm

=> y = √16 cm = 4 cm

As, LM and MN are equal so, the length of each of the 2 equal sides is 4 cm .

**
**