Can you explain how to do this sum with all the steps

Dear Student2a-12 2a-12 2a2a-12  -122a-12 = 4a2 -(2a×12) -(12×2a) +(12×12)= 4a2 -a-a+14= 4a2-2a+14 2a-12 2a-12   = 4a2-2a+14 Regards

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