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Can you please explain it also as I cant understand the steps! and steps are very important to know.. so please help me

Q. The measured value of a physical quantity exceeds its error by an amount of 75 units. If the percentage error is 15 %, then what is the value of the physical quantity?

$Percentageerrorinaquantityisgivenby-\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\%Error=\frac{\Delta x}{x}\times 100\phantom{\rule{0ex}{0ex}}Here,\Delta xisabsoluteerror(differenceinmeasurementwithrespecttotruevalue)\phantom{\rule{0ex}{0ex}}andxistruevalue\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Henceforthegivenproblem\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}15=\frac{75}{x}\times 100\Rightarrow \overline{)x=\frac{75}{15}\times 100=500units}$

Regards.

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