Car moving at speed 'u', applied brakes with constant retardation. If speed of car reduces to ?u/2 in 30 Minuttes , then total distance travelled by car before coming to rest is
V=U+at therefore U/2=U+30/60*A therrefore A=-U.. now apply s=ut + 1/2 a t^2..therefore S=u/2+u/8=5u/8.. then applu V^2-u^2=2AS ND again by considering u as U/2 and a to be equal to -A.. AND V=0 FIND THIS DISTANCE.. DEN ADD THE PREVIOUS DISTANCE CALCULATED ND THIS DISTANCE...:)